National Institute of Informatics - Digital Silk Road Project
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Scientific Results of a Journey in Central Asia, 1899-1902 : vol.1 |
10 April 1900. Tusun-tschapghan. | |
10 April 1900. Kum-tschapghan. | |
22 Sept. 1899. Schakal-otak. |
32
THE TARIM RIVER.
We get by numerical calculation
according to method I according to method II
A dm Va
m3
2 6 0'24 - 7 8.15 m2 2.6o5 m 0.3332
sec. sec.
3
2 6 24 m 7 8.03 m2 2.601 m 0.3363 m
sec. sec.
Fig. 37. Left. r o April 1900. b = 22.o metres. n = 11 Tusun-tschapghan. Right.
p . . 1.06 2.87 4.67 4.8o 4.36 3.75 2.41 I.30 0.6z 0.16 metres
v/k . . 35.o 52.o 45.25 41.o 40.o 37.2 30.3 34.5 18.5 28 k second
The results obtained are
according to method I
according to method II
Q
m3
19'51 sec.
m3
19.39 sec.
A dm Vm
5 2.6o m2 2.391 m 0.3709 m
sec.
5 2.00 m2 • 2.364 m 0.3728 m
sec.
Fig. 38. Left. ro April 190o. b = 22.6 metres. n = 1 r Kum-tschapghan. Right.
p . . 0.46 0.88 I.16 I.88 I.48 0.86 1.63 I.99 1.96 I.37 metres
v/k . 2.00 8.o 28.7 26.3 19.5 I. 2. metre
3• 9.5 4 7 47•0 5 3 45.7 second
Here the results are
Q A dm Vm
m3
according to method I 8 52 - 2 7.86 m2 1.233 m0.3058 m
sec. sec.
according to method II 8 58 m3 28.o9 m2 1.243 m 0.3055 m
sec. sec.
Fig. 39. Left. 22 Sept. 1899. h = 35.3 metres. n = 6 Schakal-otak. Right.
ft 3.72 4.98 4.77 3.09 1.23 metres
v/k . . . 83.o 78.5 71.o 53.5 4.5 1 metre
k second
And the results work out thus
Q A dm
according to method I 68 30 m3 109.03 m2 3.089 m
sec.
according to method II 66 16 m3sec. 104.66 m2 2.965 m
0.6264 m
sec.
0.6321 -
sec.
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